9.1.6 Checkerboard V1 Codehs Today

The solution to CodeHS 9.1.6: Checkerboard, v1 involves creating an 8x8 grid of zeros and then using nested loops to modify the values in specific rows to represent checker pieces. Logic Breakdown

Output:

1 0 1 0 1 0 1 00 1 0 1 0 1 0 11 0 1 0 1 0 1 00 0 0 0 0 0 0 00 0 0 0 0 0 0 00 1 0 1 0 1 0 11 0 1 0 1 0 1 00 1 0 1 0 1 0 1 9.1.6 checkerboard v1 codehs

// 1. Create a new Rectangle object Rectangle rect = new Rectangle();

# Create an 8x8 grid of zeros board = [] for i in range(8): board.append([0] * 8) Use code with caution. Copied to clipboard 2. Apply the Checkerboard Logic The solution to CodeHS 9

Create the 8x8 checkerboard

for i in range(8): row = [] for j in range(8): # Check if the sum of row and column indices is even if (i + j) % 2 == 0: row.append("red") else: row.append("black") board.append(row) Copied to clipboard 2

def print_board(board): for row in board: print(" ".join([str(x) for x in row])) # 1. Create an 8x8 board of 0s board = [] for i in range(8): board.append([0] * 8) # 2. Assign 1s to the top 3 and bottom 3 rows for i in range(8): for j in range(8): if i < 3 or i > 4: board[i][j] = 1 # 3. Output the result print_board(board) Use code with caution. Copied to clipboard